# Voltage and loops of transformers – problems and solution

1. Based on the above table, find R and P.

Solution

Transformer’s equation :

Vs Np = Ns Vp dan Vp Ip = Vs Is

Vs = secondary voltage, Vp = primary voltage, Ns = secondary loops, Np = primary loops, Ip = primary current, Is = secondary current

Primary voltage (Vp)

Vp Ip = Vs Is

Vp (4) = (10)(80)

Vp = 800 / 4

Vp = R = 200 Volt

Secondary loops (Ns)

Vs Np = Ns Vp

(10)(600) = Ns (200)

6000 = 200 Ns

Ns = 6000 / 200

Ns = P = 30 loops

Read :  Applications of Bernoulli's principle

2. Based on the above table, find K and L.

Solution :

Secondary current (Is) of transformer 1 :

Vp Ip = Vs Is

(200)(3) = (300)(Is)

Is = 600 / 300

Is = K = 2 A

Secondary voltage (Vs) of transformer 2 :

Vp Ip = Vs Is

(40)(0,75) = Vs (1)

Vs = L = 30 Volt

Read :  Net work, gravitational potential energy, kinetic energy – problems and solutions

3. Based on the table above, find P and Q.

Solution :

Primary voltage (Vp)

Vs Np = Ns Vp

(220)(300) = (600) Vp

(220)(3) = (6) Vp

660 = 6 Vp

Vp = 660 / 6

Vp = P = 110 Volt

Primary current (Ip)

Vp Ip = Vs Is

(110)(Ip) = (220)(2)

(110)(Ip) = 440

Ip = 440 / 110

Ip = Q = 4 A

Read :  Nonuniform linear motion - problems and solutions