Atomic binding energy – problems and solutions
1. Find X!
A. proton
B. electron
C. deuteron
D. triton
E. Alpha particle
Solution
14 + 1 = 15 —> 15 – 14 = 1
7 + 0 = 7 —> 7 – 6 = 1
The correct answer is A.
2. Find X!
A. electron
B. proton
C. neutron
D. deuteron
E. triton
Solution
138 + 93 + 5 = 236 —> 236-235 = 1
56 + 41 – 5 = 92 —> 92-92 = 0
The correct answer is C.
3.
If mass of Be = 9.033 amu, He = 4.002 amu, C = 12.001 amu, n = 1.009 amu. 1 amu ~ 931 MeV, then what is the energy produced.
Solution :
Mass of reactans and products :
Mass of reactans (mreactans) = 9.033 amu + 4.002 amu = 13.035 amu
Mass of products (mproduct) = 12.001 amu + 1.009 amu = 13.01 amu
Mass lost during reaction:
Δm = mreactan– mproducts
Δm = 13.035 amu – 13.01 amu
Δm = 0.025 amu
The mass lost in the fusion reaction is 0.025 amu.
1 amu is equivalent to 931 MeV of energy. 0.025 amu equivalent to the energy of 0.025 x 931 MeV = 23.275 MeV.